Hi,
I have a table which have different tables say T1,2,3 scheduled Daily , T4,5 scheduled weekly and T6 monthly once. Schedule type is differentiated with the help of flag like below,
My job is scheduled in crontab accordingly . Is there a way to instruct the same job to run for all the instances ? I have tried with comparing system time and having a entry on the table accordingly to compare and run. But that seems tricky, if there is a delay in starting/processing of a job :( Ideas are welcome
I have a table which have different tables say T1,2,3 scheduled Daily , T4,5 scheduled weekly and T6 monthly once. Schedule type is differentiated with the help of flag like below,
| Tables | Schedule_type | |
| T1 | 1 | Daily |
| T2 | 1 | |
| T3 | 1 | |
| T4 | 2 | Weekly |
| T5 | 2 | |
| T6 | 3 | Monthly |
My job is scheduled in crontab accordingly . Is there a way to instruct the same job to run for all the instances ? I have tried with comparing system time and having a entry on the table accordingly to compare and run. But that seems tricky, if there is a delay in starting/processing of a job :( Ideas are welcome